cse • paper_2 • quantum_mechanicscse-2024-subject-05-004
Quantum wavefunction — UPSC CSE 2024 Physics PYQ
Buy PYQ Solution Manual →Find the energy of the particle of mass m moving in a potential field V(x) = \frac{2\hbar^2 b^2 x^2}{m} for which the time independent wave function is \psi(x) = \exp(-bx^2). Here b is a constant.
Discussion (0)
Sign in to post a solution, derivation, or discussion.
No comments yet. Start the conversation!