cse • paper_1 • thermal_physicscse-2009-subject-04-004
[UPSC CSE 2009] Statistical Physics (Q306, 20M)
Energy distribution for n_i particles in classical statistical mechanics is given by n_i = g_i e^{-\alpha -\beta \varepsilon_i} where \alpha and \beta are constants. g_i is the single particle states in the i\text{ th} level. Using equipartition theorem, show that correct thermodynamic interpretation is \beta = \frac{1}{kT} (Use \int_0^\infty e^{-x} x^{1/2} \, dx = \frac{\sqrt{\pi}}{2} and \int_0^\infty e^{-\beta x} x^{3/2} \, dx = \frac{3\sqrt{\pi}}{4\beta^{5/2}})
Discussion (0)
Sign in to post a solution, derivation, or discussion.
No comments yet. Start the conversation!