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cse • paper_1 • thermal_physicscse-2006-subject-04-002

Joule–Thomson effect — UPSC CSE 2006 Physics PYQ

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Using thermodynamic principles show that the Joule-Thomson coefficient \mu can be expressed as \mu = \frac{1}{C_p} \left[ T \left( \frac{\partial V}{\partial T} \right)_p - V \right] . Calculate the value of \mu for an ideal gas and interpret your result physically.

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