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cse • paper_1 • electrodynamicscse-1998-subject-03-002

Polarisation of light — UPSC CSE 1998 Physics PYQ

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What was the basis for light to be accepted as an electromagnetic wave ? The \vec{E} vector in a light wave polarised in the (x, y) plane is expressed as \vec{E}(x, y, z, t) = \vec{E}_0 \sin\left[\omega t - k(x + y)\right] Determine the propagation and the polarisation vectors.

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