cse • paper_1 • thermal_physics
[UPSC CSE 1988] Thermodynamics (Q233, 30M)
Find the temperature at which root mean square velocity of nitrogen molecules in earth’s atmosphere equals the velocity of escape from the earth’s gravitational field. Mass of N_2 atom = 23.24 \times 10^{24}\text{ g}. Mean radius of earth = 6370\text{ km}.
Discussion (0)
Sign in to post a solution, derivation, or discussion.
No comments yet. Start the conversation!